You are not logged in.
Pages: 1
I always wondered about dx.dx ? How to handle that ? If I consider a small triangle with height = dy, and width dx, then
hypotenuse dh = sqrt(dy^2 + dx^2). Now suppose I want to differentiate this equation wrt time t, what we will get ?
Offline
Offline
Thanks for the reply. Hopefully I will make some big leap forward with this thing.
Offline
Correction:
Take the positive square root if h is increasing with respect to t, the negative square root if decreasing.
Offline
Pages: 1