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**pokrate****Member**- Registered: 2012-11-16
- Posts: 13

I always wondered about dx.dx ? How to handle that ? If I consider a small triangle with height = dy, and width dx, then

hypotenuse dh = sqrt(dy^2 + dx^2). Now suppose I want to differentiate this equation wrt time t, what we will get ?

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**scientia****Member**- Registered: 2009-11-13
- Posts: 222

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**pokrate****Member**- Registered: 2012-11-16
- Posts: 13

Thanks for the reply. Hopefully I will make some big leap forward with this thing.

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**scientia****Member**- Registered: 2009-11-13
- Posts: 222

Correction:

Take the positive square root if *h* is increasing with respect to *t*, the negative square root if decreasing.

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