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•  » What is the point (ordered pairs) of Graph of a function?

## #1 2012-12-27 10:44:31

21122012
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### What is the point (ordered pairs) of Graph of a function?

Who will be able to give me the irrefragable answers.
The question N1:
"What is the point (ordered pairs) of Graph of a function for the function (if each vertical line is the  function value)?"

I will prompt:

Both top limits - are coordinates of this point. And its value is equal to

a tangent of angle of an inclination of a tangent (
).

What is the point (ordered pairs: (
))

of Graph of a function for the function: (
)

(if each vertical line is the  function value (
))?

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #2 2012-12-27 20:41:17

bob bundy
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### Re: What is the point (ordered pairs) of Graph of a function?

hi 21122012

I am confused by what you have asked.

Are you looking for help on the fundamental theorem of calculus?

Are you wanting to know A(x) in my diagram?

Bob

You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

## #3 2012-12-28 05:34:38

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

#### bob bundy wrote:

hi 21122012

I am confused by what you have asked.

Are you looking for help on the fundamental theorem of calculus?

Are you wanting to know A(x) in my diagram?

Bob

No!

I want to have the answer to a question: what is the point

for function

You understand?

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #4 2012-12-28 05:40:18

anonimnystefy
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### Re: What is the point (ordered pairs) of Graph of a function?

What are x_0 and y_0?

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #5 2012-12-28 06:01:41

bob bundy
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### Re: What is the point (ordered pairs) of Graph of a function?

Next question?

Bob

You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

## #6 2012-12-28 06:05:08

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

#### anonimnystefy wrote:

What are x_0 and y_0?

http://en.wikipedia.org/wiki/Integration_by_parts

You understand???!!!

What is ordinate and abscissa?

You understand:

Last edited by 21122012 (2012-12-28 06:09:40)

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #7 2012-12-28 06:06:47

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

#### bob bundy wrote:

Next question?

Bob

You wrote everything correctly but a question didn't answer.

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #8 2012-12-28 06:09:59

anonimnystefy
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### Re: What is the point (ordered pairs) of Graph of a function?

You should really explain the notation

and
.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #9 2012-12-28 06:22:20

bob bundy
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### Re: What is the point (ordered pairs) of Graph of a function?

I thought I did answer a question.

If it wasn't the question you were asking, then you will have to re-phrase your question.

Bob

You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

## #10 2012-12-28 06:30:59

scientia
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### Re: What is the point (ordered pairs) of Graph of a function?

#### bob bundy wrote:

Next question?

Bob

You wrote everything correctly but a question didn't answer.

Is that the way you want to see your "answer" being written?

## #11 2012-12-28 06:34:49

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

#### anonimnystefy wrote:

You should really explain the notation

and
.

Well!!!

It proves that VTSUALISATION is my development!!!!

Look on Visualisation:

You understand?!

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #12 2012-12-28 06:36:43

anonimnystefy
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### Re: What is the point (ordered pairs) of Graph of a function?

No, not really.

What is [x_1]?

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #13 2012-12-28 06:37:04

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

#### bob bundy wrote:

Next question?

Bob

You wrote everything correctly but a question didn't answer.

Is that the way you want to see your "answer" being written?

That you write to me same. I am not an idiot and I understand that you write. I am itself I know. Read a question and answer it.

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #14 2012-12-28 06:40:31

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

#### anonimnystefy wrote:

No, not really.

What is [x_1]?

[x_1] is piece on the OX axis with a length:

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #15 2012-12-28 06:48:55

bob bundy
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### Re: What is the point (ordered pairs) of Graph of a function?

In Russian, perhaps, so we can translate it correctly.

Bob

You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

## #16 2012-12-28 06:50:27

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

Understand that you explain me what role function for a point of GRAF plays. And I ask what role a point of the GRAF plays for function. You understand a difference?

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #17 2012-12-28 06:53:09

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

#### bob bundy wrote:

In Russian, perhaps, so we can translate it correctly.

Bob

Вы пишете мне объяснение какую роль играет функция для точки графика функции. Функция определяет ординату точки. Это понятно. Теперь объясните мне какое вообще отношение к функции имеет точка графика функции?

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #18 2012-12-28 07:05:07

anonimnystefy
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### Re: What is the point (ordered pairs) of Graph of a function?

Here is a rough translation (luckily, Serbian and Russian are very much alike):

You write to me the explanation of the role of the function for a point of the graph. The function determines the ordinate of the point. That is clear. Now explain to me what general relation does the point of the graph have to the function.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #19 2012-12-28 07:31:14

bob bundy
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### Re: What is the point (ordered pairs) of Graph of a function?

Thanks Stefy,

That is very helpful.  The on-line translators (I tried three) all gave goobledegook.

But I still don't know what he is asking for.  Have you any idea?

Bob

You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

## #20 2012-12-28 07:36:52

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

You write to me the explanation of the role of the function for a point of the graph. The function determines the ordinate of the point. That is clear. Now explain to me what relation does the point of the graph have to the function.

Yes! It's true!

Look this:

Last edited by 21122012 (2012-12-28 07:38:32)

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #21 2012-12-28 07:42:55

bob bundy
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### Re: What is the point (ordered pairs) of Graph of a function?

I have looked at your picture.

It makes no sense to me.

Bob

You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

## #22 2012-12-28 07:45:10

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

Circle - the geometrical point

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

## #23 2012-12-28 07:48:38

anonimnystefy
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### Re: What is the point (ordered pairs) of Graph of a function?

Hi Bob

You're welcome.

I think what he wants is interpolation...

Last edited by anonimnystefy (2012-12-28 07:57:47)

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #24 2012-12-28 07:56:20

bob bundy
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### Re: What is the point (ordered pairs) of Graph of a function?

#### 21122012 wrote:

Circle - the geometrical point

You want a circle with radius = zero ?

I cannot see this circle.  It is too small.

But I will imagine it.

Please go on to lesson 2.

Bob

You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

## #25 2012-12-28 08:06:59

21122012
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### Re: What is the point (ordered pairs) of Graph of a function?

You don't see, but sees a tangent of angle of an inclination of a tangent to the Graph of a function. Ask it, he will tell you about each point of the Graph of a function.

Genes and molecules too it isn't visible but for this purpose there is an imagination

"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"

Thomas Ioannes Stiltes. ...                                                 I made it!

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