Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**mukesh****Member**- Registered: 2010-07-18
- Posts: 31

using co-ordinate geometry show that median of an equilatral triangle is perpendiculur to its opposite side.

Plse help me sir

Offline

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,548

hi mukesh,

Coordinate geometry is an unusual way to do this but OK; it can be done.

Firstly, you need to choose your triangle.

I'd keep things simple by having the base going from (0,0) to (2,0).

That makes the midpoint of the base at (1,0)

The vertex will be at (2cos60, 2sin60) = (1,√ 3)

The median joins the midpoint of the base to the vertex so that is the line x=1, which is at right angles to the base.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

Pages: **1**