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#1 2013-02-15 14:29:20

{7/3}
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Registered: 2013-02-11
Posts: 210

P-norm

The p-norm of a vector(in 2d) is (|x|^p+|y|^p)^(1/p) my question is can p be 0,fraction or nagetive?


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#2 2013-02-15 20:12:47

zetafunc.
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Re: P-norm

If I recall correctly, p can be any real number apart from 0.

#3 2013-02-15 20:28:17

anonimnystefy
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From: The Foundation
Registered: 2011-05-23
Posts: 15,657

Re: P-norm

Actually, p must be a real number greater or equal to 1.


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#4 2013-02-15 23:54:13

{7/3}
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Registered: 2013-02-11
Posts: 210

Re: P-norm

Why isn't nagetive number or fractions<1 allowed?


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#5 2013-02-16 06:54:15

anonimnystefy
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From: The Foundation
Registered: 2011-05-23
Posts: 15,657

Re: P-norm

Because it wouldn't be a norm (it would give zero values if any of the coordinates is 0).


“Here lies the reader who will never open this book. He is forever dead.

“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

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#6 2013-02-16 16:16:18

{7/3}
Member
Registered: 2013-02-11
Posts: 210

Re: P-norm

Oh,thanks.


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