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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 293

hi

If I have the 1 circle, 3 triangles and two hexagons and they're in a bag and pick them two times with return what is the probability of getting exactly one hexagon ?

I get 3/9 but the answer is 4/9....

help pls thanks

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

Hi;

4 / 9 is the correct answer.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 293

Could you explain me how you did it ? I get 12/36 and not 16/36....

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

Hi;

For school problems you should be using the simplest ideas, especially when you are stuck. Did you draw a tree?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 293

yes. and what do you mean by simplest ideas ?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

You always have to get an answer. One way, or the other.

Let me show you how to draw the tree without drawing it:

This is your set of possibilities,

now the triangles and the circle we are not interested in so we give them the generic label of "other." Your set becomes,

the tree looks like this,

oh

ho

oo

hh

do you follow?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 293

ok...

explain this

oh

ho

oo

hh

*Last edited by Al-Allo (2013-03-29 11:48:30)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

Hi;

oh = ( 4 / 6 ) ( 2 / 6 )

ho = ( 2 / 6 ) ( 4 / 6 )

oo = who cares

hh = who cares

Can you finish that?

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 293

it gives 16/36

but i still don't understand the logic behind it how did you get those numbers ?ty

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

ho means I drew a hexagon and then something else. The probability of drawing a h is 2 / 6 because there are 2 of them out of the total 6. Then I draw an o, the probability is ( 4 / 6 ) because there are 4 of them out of 6. Same logic for oh.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 293

i think im gonna re read the problem... im not sure of even understanding what they want ..ty for your help

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

If you are not sure of the problem then please just copy it over here.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 293

Here :

An aleatory experience consists of turning an arrow on a roulette two times. (3 triangles, 1 circle, and two hexagon)

Question : What is the probability of obtaining exactly one haxagon.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

The question is the same as the one you posted in post #1. The answer and logic are the same, 4 / 9. I can draw a tree if it will help.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 293

Yes, please. !

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

Here is the full tree do you know what to do from here? Pay no attention to the numbers after the words circle triangle or hexagon.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**Al-Allo****Member**- Registered: 2012-08-23
- Posts: 293

anyway, ill go through what you posted tomorrow, i dont have the energy tonight to think about it. thanks for your efforts to help.*curiously, when you get stuck on problems, how do you operate to solve them? any principles,etc. ?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

For probability and combinatorics when stuck I do it the hard way. No calculations, draw trees or count them all by hand.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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