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**cooljackiec****Member**- Registered: 2012-12-13
- Posts: 160

In ,quadrilateral QRTS we have QR = 11,QS = 9 , and ST=2. Sides RQ and ST are extended past Q and S , respectively, to meet at point P. If PS=8 and PQ=5, then what is RT?

I see you have graph paper.

You must be plotting something

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,532

I would say 18.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**cooljackiec****Member**- Registered: 2012-12-13
- Posts: 160

thanks! my teacher gives me hard hwk.

In ,

points X and Z are on AB and Y is on AC such that XY||BC and ZY||XC. If AZ=8 and , ZX=4 then what is XB ?I see you have graph paper.

You must be plotting something

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,532

Do you understand why the answer is 18 for the last one?

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**cooljackiec****Member**- Registered: 2012-12-13
- Posts: 160

yah i get it. you add some extra lengths to 5 and 8 and then you get similar triangles. i did not see that at first.

I see you have graph paper.

You must be plotting something

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,532

Well, for the second problem, I would say the answer is 6.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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