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If

is a factor of the polynomials and , prove that'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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That is the problem (n-k) is the factor

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,168

hi Agnishom,

I suggest you check the question. If it started " x + k is a factor....." then that result can be found using Nehushtan's method.

If we maintain (n-k) then since both quadratics must have factors of the form (x - a) and (x - b) that suggests x = n or x = k. The problem then de-generates and certainly doesn't give that result.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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Maybe that is a printing mistake?

My teacher told to assume (n-k) as a zero of the polynomial

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

Offline

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