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If

is a factor of the polynomials and , prove that'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

'But our love is like the wind. I can't see it but I can feel it.' -A Walk to remember

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That is the problem (n-k) is the factor

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

'But our love is like the wind. I can't see it but I can feel it.' -A Walk to remember

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,270

hi Agnishom,

I suggest you check the question. If it started " x + k is a factor....." then that result can be found using Nehushtan's method.

If we maintain (n-k) then since both quadratics must have factors of the form (x - a) and (x - b) that suggests x = n or x = k. The problem then de-generates and certainly doesn't give that result.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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Maybe that is a printing mistake?

My teacher told to assume (n-k) as a zero of the polynomial

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

'But our love is like the wind. I can't see it but I can feel it.' -A Walk to remember

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