Single-var Calculus (and otherwise)

ShivamS · 2013-05-13 05:01:37

Some problems...one at a time.

Suppose the integral was already performed on an equation. What is the simplified answer if you now take the integral from 0 to 1 for the following integrated equation:

8x^3 + 3x^2 - 4x + C

I got 7.

anonimnystefy · 2013-05-13 05:57:18

7 is correct.

ShivamS · 2013-05-13 05:59:43

Consider 'x' to be a variable. What is the derivative of 12x^4 + 10x^3 - 5x^2 + 16 with respect to x?

I get 48x^3 + 30x^2 - 10x

Also:

Consider 'x' to be a variable. What is the integral of 18x^2 - 10x + 3 with respect to x? Pick the most correct solution.

I get 6x^3 - 5x^2 + 3x + C

anonimnystefy · 2013-05-13 06:02:42

Both are correct! Good work!

ShivamS · 2013-05-13 06:07:31

Thank-you; I just thought I needed some extra practive before the exams. After that, I should be much more relaxed... Anyways, I will post some more later.

Last edited by ShivamS (2014-03-09 04:12:35)

anonimnystefy · 2013-05-13 06:12:20

You are welcome.

Okay, post the other questions when you want.

ShivamS · 2013-05-22 00:33:07

Hi; few other simple problems. Fred is standing on the ground and throws a ball up in to the air. He observes that it falls back down to the ground after 5 seconds. What was the initial velocity of the ball? I get 0 = -400 + 5V subscript 0 Thus initial velocity = 80ft / s

ShivamS · 2013-05-22 00:42:01

One more: Junita is standing on the roof of a building 192 feet tall and throws a ball up in to the air with an initial speed of 64 feet / second.

(a) Find formula for velocity and position of ball at a later time. I get v(t) = -32t + 64 And for position: y(t) = -16t^2 + 64t +192

(b) How high does the ball go? I am getting 256 feet,

(c) When does the ball hit the ground? I think this is probably wrong, but I am getting 6 seconds.

Thank-you in advance.

anonimnystefy · 2013-05-22 00:42:24

I am getting 25 m/s. Which formula are you using?

ShivamS · 2013-05-22 00:44:50

Hi Stefy; for which question are you getting that?

anonimnystefy · 2013-05-22 00:46:38

The one in post #7.

ShivamS · 2013-05-22 00:52:38

I get y(t) = Integral (-32t + v subscript 0)dt = -16t^2 + v subscript 0 t + C

So y(t) = -16t^2 + v0t (o = subscript)

So 0 = -16 * 5^2 + initial velocity * 5 = -400 + 5 (initial velocity) = -400 + 5 initial velocity

Solving gives us V0 = initial velocity = 80 ft / second

anonimnystefy · 2013-05-22 01:01:22

Shivamcoder3013 wrote:

y(t) = Integral (-32t + v subscript 0)dt

How'd you get this?

ShivamS · 2013-05-22 01:05:44

Similar to the problem in post 8. ground level will be position 0, up will be the positive direction and time t=0 will be the instant when Fred first throws the ball. The acceleration due to gravity will be a = -32. Thus dv/dt = -32, so that v(t) = -32 + C. The problem does not give any information about the velocity of the ball at any time so I use v0 to represent initial velocity. AT time t = 0, I get v(t) = -32t + v0. So, as v(t) = dr/dt, y(t) = integral (-32t + v0)dt = -16t + v0t + C.

anonimnystefy · 2013-05-22 01:11:12

But, the acceleration due to gravity is 9.81 (or 10, if you round it up) mps.

ShivamS · 2013-05-22 01:13:57

Well, the units in the problem were feet, and 9.81 is approximately 32 feet. Also, "Similar to the problem in post 8. ground level will be position 0, up will be the positive direction and time t=0 will be the instant when Fred first throws the ball. The acceleration due to gravity will be a = -32."

anonimnystefy · 2013-05-22 01:35:16

Ah, so we are both correct on the initial velocity for the one in post #7.

Let me look at the second one.

ShivamS · 2013-05-22 01:37:42

25m is 82 feet so did you simply approximate something?

anonimnystefy · 2013-05-22 01:40:38

Yeah, I took g to be 10m per second squared. I am getting approximately 24.525mps with g=9.81m per second squared.

ShivamS · 2013-05-22 01:41:58

Oh, okay. Thank-you. The second one is a bit more complicated.

anonimnystefy · 2013-05-22 02:19:11

I think all three are correct.

ShivamS · 2013-05-23 00:28:53

Okay, thank you very much. I have some more but I will post them later. Actually, here are some vector calculus questions:

Determine if the vector ﬁeld f(x, y,z)= x yzi+xzj+x yk has a potential in R3

I am getting that it does not have the potential.

anonimnystefy · 2013-05-23 00:54:22

I don't think I know what the potential of a vector is.

ShivamS · 2013-05-24 00:10:37

http://en.wikipedia.org/wiki/Vector_potential

But thank-you anyways.

ShivamS · 2013-05-27 00:29:46

Thanks a lot Stefy; the midterm exam went extremely well.

Math Is Fun Forum

#1 2013-05-13 05:01:37

Single-var Calculus (and otherwise)

#2 2013-05-13 05:57:18

Re: Single-var Calculus (and otherwise)

#3 2013-05-13 05:59:43

Re: Single-var Calculus (and otherwise)

#4 2013-05-13 06:02:42

Re: Single-var Calculus (and otherwise)

#5 2013-05-13 06:07:31

Re: Single-var Calculus (and otherwise)

#6 2013-05-13 06:12:20

Re: Single-var Calculus (and otherwise)

#7 2013-05-22 00:33:07

Re: Single-var Calculus (and otherwise)

#8 2013-05-22 00:42:01

Re: Single-var Calculus (and otherwise)

#9 2013-05-22 00:42:24

Re: Single-var Calculus (and otherwise)

#10 2013-05-22 00:44:50

Re: Single-var Calculus (and otherwise)

#11 2013-05-22 00:46:38

Re: Single-var Calculus (and otherwise)

#12 2013-05-22 00:52:38

Re: Single-var Calculus (and otherwise)

#13 2013-05-22 01:01:22

Re: Single-var Calculus (and otherwise)

#14 2013-05-22 01:05:44

Re: Single-var Calculus (and otherwise)

#15 2013-05-22 01:11:12

Re: Single-var Calculus (and otherwise)

#16 2013-05-22 01:13:57

Re: Single-var Calculus (and otherwise)

#17 2013-05-22 01:35:16

Re: Single-var Calculus (and otherwise)

#18 2013-05-22 01:37:42

Re: Single-var Calculus (and otherwise)

#19 2013-05-22 01:40:38

Re: Single-var Calculus (and otherwise)

#20 2013-05-22 01:41:58

Re: Single-var Calculus (and otherwise)

#21 2013-05-22 02:19:11

Re: Single-var Calculus (and otherwise)

#22 2013-05-23 00:28:53

Re: Single-var Calculus (and otherwise)

#23 2013-05-23 00:54:22

Re: Single-var Calculus (and otherwise)

#24 2013-05-24 00:10:37

Re: Single-var Calculus (and otherwise)

#25 2013-05-27 00:29:46

Re: Single-var Calculus (and otherwise)

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