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**jafrevelar****Member**- Registered: 2013-06-15
- Posts: 8

Can somebody help me with this problem? I dont have any idea how to answer it.....

Divide (4x^3yz^3+3x^4y^2z+4x^2y^2z^3+3x^3y^3z-4x^2yz^4-3x^3y^2z^2) by (x+y-z)

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,247

Hi;

Are you supposed to do it by hand?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**jafrevelar****Member**- Registered: 2013-06-15
- Posts: 8

Yes. And i need to show a solution for it..

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,247

There is the solution up there in post #2.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**phanthanhtom****Member**- Registered: 2012-06-22
- Posts: 215

Prove that by cross multiplication. Multiply right hand side in Bobbym's equation with your trinomial. That's it.

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**jafrevelar****Member**- Registered: 2013-06-15
- Posts: 8

Im sorry I cant understand it T_T i dont know where to start. :"(

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**jafrevelar****Member**- Registered: 2013-06-15
- Posts: 8

Please help me

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,247

With the multiplication?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**jafrevelar****Member**- Registered: 2013-06-15
- Posts: 8

Thank you i already understood it!!!!!! Your a great help thank you so much

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**jafrevelar****Member**- Registered: 2013-06-15
- Posts: 8

Just another thing, im still having a hard time understanding how you come up with the answer. Can you please explain it? Just one last favor pls.

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**jafrevelar****Member**- Registered: 2013-06-15
- Posts: 8

Pleaseeee,..........m

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,247

I used a computer! But if you show me what method you are supposed to use I will assist with the steps?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**jafrevelar****Member**- Registered: 2013-06-15
- Posts: 8

I tried to used long division

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**phanthanhtom****Member**- Registered: 2012-06-22
- Posts: 215

Polynomial division techniques can be found on the main website. Type 'polynomial division' into the search box.

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,426

hi jafrevelar

Welcome to the forum.

In the screen shot below I have shown my layout for this. (note: it will be beneficial to keep terms in neat columns)

(i) I re-ordered the terms to start with the highest power of x, and then in descending powers. Make sure the signs go with the terms.

(ii) Ask what must I multiply by x to get

(iii) now multiply (x + y - z) by this amount and put the results below. Line up matching terms to make the subtraction easier.

(iv) Subtract and write in the remaining terms.

(v) Ask what must I multiply by x to get

(vi) Subtract to get the remainder. This is zero so the division is complete.

Hope that helps,

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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