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#1 2016-09-19 09:50:57
- peter010
- Member
- Registered: 2016-09-05
- Posts: 22
Why is there a constant of Integration?
Hello,
In my high school, i was told to add a constant C to the results generated from Indefinite Integration! but I did not know why should I do so!! This video illustrates the reason behind this:
https://www.youtube.com/watch?v=9NIFMp6sx7U
Last edited by peter010 (2016-09-19 09:53:25)
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#2 2016-09-19 12:41:09
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Why is there a constant of Integration?
Hi;
Seems clear enough, you should understand it now.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#3 2016-09-19 20:47:15
- Bob
- Administrator
- Registered: 2010-06-20
- Posts: 10,803
Re: Why is there a constant of Integration?
hi peter010
Very clear. Thanks,
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob 
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#4 2016-09-20 02:46:24
- peter010
- Member
- Registered: 2016-09-05
- Posts: 22
Re: Why is there a constant of Integration?
Hi
I am very happy you rated it as a clear material )
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#5 2016-09-20 03:46:27
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Why is there a constant of Integration?
Hi;
A picture is worth a thousand words and a video is a lot of pictures.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#6 2025-10-03 01:55:47
- mycalsuite
- Member
- Registered: 2025-09-10
- Posts: 56
- Website
Re: Why is there a constant of Integration?
Finding all of a function's antiderivatives is the goal of an indefinite integral. If F(x) = 1, then ? (?) + ?
Since a constant's derivative is zero, F(x)+C is likewise one. For this reason, we usually include "- C," which stands for the entire family of options. The constant is subsequently fixed by the beginning or boundary conditions in actual problems.
mycalsuite
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