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#1 2017-01-03 00:11:49

Mario23
Member
Registered: 2017-01-03
Posts: 27

The first 3 decimals of this number

Hello ! I've been revising for an exam lately and I came over this problem :
Find the first 3 decimals of sqrt(49n^2+0,35n) where n is a natural number different from 0.I would like a hint on how to do this because it is the first time I see something like it.

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#2 2017-01-03 05:07:40

Mathegocart
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Registered: 2012-04-29
Posts: 1,869

Re: The first 3 decimals of this number

Can you specify which value of n you mean? The integers are not specific enough, perhaps you meant a sum or limit?
And I assume it is common parlance in Europe that ,'s indicate decimals?


The integral of hope is reality.

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#3 2017-01-03 06:26:08

Mario23
Member
Registered: 2017-01-03
Posts: 27

Re: The first 3 decimals of this number

There is no specific value,n is just a positive integer(n>0).I will rewrite the exercise with math symbols :


And yes,that notation is used here for decimals.

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#4 2017-01-03 06:35:27

bob bundy
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Registered: 2010-06-20
Posts: 8,012

Re: The first 3 decimals of this number

hi

I did a quick 'experiment' with n = 1,2,3 ...10 and found the result always had a whole numbered part that is easy to compute from n, and the same decimal digits for the first three places.  [bobbym: I did some EM.  Hope you arte proud of me.]

So an answer is easy to calculate.  But how to prove it?  Working on it .......

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

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#5 2017-01-03 06:53:38

bob bundy
Administrator
Registered: 2010-06-20
Posts: 8,012

Re: The first 3 decimals of this number

Here we go......

Then you can use the general binomial theorem https://en.wikipedia.org/wiki/Binomial_ … al_theorem

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

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#6 2017-01-03 23:06:58

Mario23
Member
Registered: 2017-01-03
Posts: 27

Re: The first 3 decimals of this number

Ok so from that point I applied that theorem but what should I do next?

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#7 2017-01-04 01:31:19

bob bundy
Administrator
Registered: 2010-06-20
Posts: 8,012

Re: The first 3 decimals of this number

Use the theorem to write down the first three terms of the expansion.  Show that term two is independent of n and that later terms are sufficiently small that they will only affect the fourth decimal place and beyond.  So you will have an approximation for the expression that is valid to 3dp.

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

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#8 2017-01-04 02:47:48

Mario23
Member
Registered: 2017-01-03
Posts: 27

Re: The first 3 decimals of this number

So I should prove that


is independent of n?
EDIT:That's the only thing I can't prove so I could use a hand smile

Last edited by Mario23 (2017-01-04 03:08:03)

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#9 2017-01-04 05:32:53

thickhead
Member
Registered: 2016-04-16
Posts: 1,077

Re: The first 3 decimals of this number

Mario23 wrote:

So I should prove that


is independent of n?
EDIT:That's the only thing I can't prove so I could use a hand smile

It should be7n*{1/(280n)-1/(8*140^2*n^2)}=1/(40)-7/(8*140^2*n)


{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}

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#10 2017-01-04 08:32:37

Mario23
Member
Registered: 2017-01-03
Posts: 27

Re: The first 3 decimals of this number

Yeah,I managed to finish it from that point.Thank you all for your help!

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