Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**SpySee****Member**- Registered: 2017-09-11
- Posts: 1

Good day ~

I see there are other answers to this questions like this, but as far as I saw not for exactly what I am seeking.

Networking event: The goal is for each person to meet as many people as possible;

They may not repeat tables within day one nor may they repeat within day two - I know this is possible. However, they do not want the attendees to see the same people at the tables over the entire two day event = 7 rotations. Would you tell me if this is possible and share the breakdown? I have done it with a randomize function once and a pivot table...but both times table guests were repeated.

This is the breakdown...

We anticipate 30 participants; 5 tables (6 at a table)

Day One:

Must have three rotations - they may never repeat the same table twice (on this day) nor do they want them to see the same people at a table (however I think with a group of 30 this may be impossible...?)

Day Two:

Must have four rotations - they may never repeat the same table twice (on this day) nor do they want them to see the same people at a table.

Looking forward to your expert advise.

Thank you.

Offline

**Alg Num Theory****Member**- Registered: 2017-11-24
- Posts: 337
- Website

When I saw the thread title, I thought it was going to be about the dihedral group of degree 30 (order 60)!

Anyway, I see you what you mean. I don’t think it’s possible. With more people than tables, a rotation will mean that at least two people sitting at one table will have to sit at the same table and see each other again.

Offline

Pages: **1**