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**alex77****Member**- Registered: 2019-12-02
- Posts: 8

https://ibb.co/txRKdsp

And another example when the series are convergent but It is hard for me to solve it:

https://ibb.co/jV2zLTN

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**alex77****Member**- Registered: 2019-12-02
- Posts: 8

No one?

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**George,Y****Member**- Registered: 2006-03-12
- Posts: 1,372

(n+1)/(3n+2)

> (n+1)/(3n+3) = 1/3

(m-n) * 1/3 does not satisfy Cauchy Critirion

thus ∑1/3 is not convergent (even without using Cauchy Critirion)

How can ∑(n+1)/(3n+2) , a larger one, converge?

**X'(y-Xβ)=0**

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