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If we were wondering, are all legendary people smart? Or do you have to be smart to be legendary? Or does being smart automaticly make me legendary? Well one little test will answer this for us.
All of these questions are basicly asking if smart = legendary. If any substitution of one for the other produces a false statement, it is not always true. (though it would not prove it is never true)
For this proof you need to know the transiative butt property which our friend strongbad can demonstrate here:
http://homestarrunner.com/sbemail3.html
Ok. So if butt iq <= head iq, read it backwards and it confirms if you have a smart butt, it garentees you have a smart head.
smart head >= smart butt
if it were true legendary = smart then:
smart head >= legendary butt
For those who find this statement confusing it basicly means that the smartness of a persons head is greater then or equal to the legendarity of their butt. But Jennifer Lopez clearly demonstrated a legendary butt does not garentee a smart head therefore the substitution "legendary = smart" was invalid.
Hence legendary does not necessarily equal smart. Quod Erat Demonstratum.
Last edited by mikau (2006-02-05 14:59:53)
A logarithm is just a misspelled algorithm.
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I concur! Or perhaps it renders the transiative butt property null and void?
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Alternatively, it could mean that stupidity is not the inverse of intelligence.
Or, it could mean that there's a difference between having a smart head and being smart.
Double-or, it could mean that I should stop looking too much into this as it's just a joke. ^_^
Why did the vector cross the road?
It wanted to be normal.
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Hey the deeper we dig into this the funnier it gets! :-D
A logarithm is just a misspelled algorithm.
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Its kinda weird for an equation i mean a legendary butt?
(im an ALIEN ) im kool (WHAT You cant steal my fridge!)]
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