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#1 2006-03-09 17:56:30

ganesh
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Ration, Proportions, Work, Manpower

RPWM # 1

A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takes double that of C to complete the same task. They are paired in groups of two each. One pair takes two-thirds the time needed by the second pair to complete the work. How are the four paired?

Character is who you are when no one is looking.

#2 2006-03-09 17:58:17

ganesh
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Re: Ration, Proportions, Work, Manpower

RPWM # 2

A, B and C went to buy things from a wholesale market. They had a combined sum of \$ 900. A spent 80%, B spent 70% and C spent 75% of their respective amounts. Now the ratio of amounts left with them is 4 : 9 : 10. Find the ratio of amounts they had in the beginning.

Character is who you are when no one is looking.

ashwil
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#2

#4 2006-03-11 02:13:39

ganesh
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Re: Ration, Proportions, Work, Manpower

Excellent, Ashwil!

Character is who you are when no one is looking.

#5 2006-03-12 02:40:11

ganesh
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Re: Ration, Proportions, Work, Manpower

RPWM # 3

Three vessels contain mixtures of milk and water in the ratio 3:1, 4:1, and 5:1. The contents of the three vessels are mixed in the ratio x:y:1. If the resulting mixture contains milk and water in the ratio 7:1, find y in terms of x.

Character is who you are when no one is looking.

#6 2006-07-13 07:09:02

All_Is_Number
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Re: Ration, Proportions, Work, Manpower

Last edited by All_Is_Number (2006-07-13 07:10:13)

You can shear a sheep many times but skin him only once.

#7 2006-07-13 07:24:50

All_Is_Number
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Re: Ration, Proportions, Work, Manpower

ganesh wrote:

RPWM # 3

Three vessels contain mixtures of milk and water in the ratio 3:1, 4:1, and 5:1. The contents of the three vessels are mixed in the ratio x:y:1. If the resulting mixture contains milk and water in the ratio 7:1, find y in terms of x.

I'm not sure there is a valid solution to this problem. If 3:1 implies 3 parts milk to one part water, and 4:1 implies 4 parts milk to one part water, etc; there is no way to produce a solution of seven parts milk to one part water with the three solutions available. They will all have too much water. On the other hand, if 3:1 means three parts water to one part milk, etc; all possible solutions will have too much milk. One of the initial solutions must have a ratio higher than 7:1 in order to end up with a solution of 7:1. As the problem currently stands, I believe there are no real solutions.

You can shear a sheep many times but skin him only once.

#8 2006-07-13 10:02:41

MathsIsFun

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Re: Ration, Proportions, Work, Manpower

I think that's right, AllIs.

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

tan
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A & C , B&d

#10 2011-03-01 19:11:42

G-man
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Re: Ration, Proportions, Work, Manpower

#3 isn't a valid problem because the ratio of the final mixture Should be between 3:1 & 5:1.
Still I calculated this.

Last edited by G-man (2011-03-01 19:13:36)

Maths!......