Math Is Fun Forum
Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °
You are not logged in.
- Topics: Active | Unanswered
Pages: 1
#1 2006-06-23 11:58:44
- fusilli_jerry89
- Member
- Registered: 2006-06-23
- Posts: 86
trig
does anyone know how to get this question? I got pi/2 and 3pi/3.
√2 sin² -sin = 0 Solve for values of sin. 0<x<2pi
Offline
#2 2006-06-23 12:52:58
- Ricky
- Moderator
- Registered: 2005-12-04
- Posts: 3,791
Re: trig
Is it sin(x) for each?
sin(x) (√2sin²x - 1) = 0
sin(x) = 0 or sin²x = √2/2
x = 0, pi for the first, and sinx = √√2 / √2 which is 2^(3/4) / 2
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
Offline
#3 2006-07-21 00:45:48
- Kurre
- Member
- Registered: 2006-07-18
- Posts: 280
Re: trig
fusilli_jerry89 wrote:
3pi/3.
3pi/3=Pi
Offline
#4 2007-02-28 17:41:19
- JaneFairfax
- Member
- Registered: 2007-02-23
- Posts: 6,868
Re: trig
Ricky wrote:
sin(x) (√2sin²x - 1) = 0
Its actually
Thus the solutions are
Last edited by JaneFairfax (2007-02-28 17:52:30)
Offline
Pages: 1