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Can some one help me here im doin some trig and ive no idea how to work out the angle marked x ok im given 2 sides the opposite and hypotinuse no angles are given, how do i work this out??
Since sin x = opposite/hypotenuse, you can figure out the angle as x = sin-¹(opposite/hypotenuse).
Do you know about sin-¹?
This page may be helpful with some trigonometry, if you forget what each trigonometric ratio is:
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hmm i know that thats inverse sine but apart form that i have no idea what it means.
u can find out angles with that yeah?
Yes. For example, if our angle is y and the opposite side is 1 and the hypotenuse is 2, then sin y = 1/2 and y = sin-¹(1/2) = 30°. You might need a table of values for inverse trigonometric ratios or a calculator. After a while you'll start to memorize some of the values though .
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A little more detailed version:
The inverse sin function is defined in such a way so that:
sin-¹(sin(x)) = x
So:
sin(y) = 1/2
sin-¹(sin(y)) = sin-¹(1/2)
y = sin-¹(1/2)
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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hmm i know that thats inverse sine but apart form that i have no idea what it means.
u can find out angles with that yeah?
And if you need any practice, just try this exercise: http://www.mathsisfun.com/forum/viewtopic.php?id=4213
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