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Please convert the equation into exponential form:
X=log4Y
Thanks
Recall that the base-4 logarithm with argument y is the function that gives you "what number 4 needs to be raised to, in order to get y", and the equation says: "this number which 4 needs to be raised to, is x".
Thus, this is the same as saying: 4^x = y. Which is in exponential form.
If you like a more algebraic method:
x = log4(y)
apply the change of base formula logb(t) = ln(t)/ln(b):
x = ln(y)/ln(4)
x*ln(4) = ln(y)
recall that k*ln(t) = ln(t^k):
ln(4^x) = ln(y)
exponentiate both sides:
e^(ln(4^x)) = e^(ln(y))
4^x = y
Same thing.
The second method is better if you remember those formulas and it requires less thinking.
another way is to take the 'Antilog base 4 ' of both sides:
antilog4(x) = antilog4(log4(y))
4^x = y
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Please convert the equation into exponential form:
X=log4Y
Thanks
X = log(4Y) is the same as 10^X = 4Y
Notice polylog and I have interpreted your problem in two different ways. Whoever interpreted it correctly offers the answer you seek.
You can shear a sheep many times but skin him only once.
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