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**Neha****Member**- Registered: 2006-10-11
- Posts: 173

Write the quadratic equation with a lead coefficient of 1 whose roots are 2 + sqrt5 and 2 - sqrt5 .

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

If the lead coefficient is 1, then by the quadratic equation, the solution will be x = [-b ±√(b² - 4c)]/2.

We are told that the roots are 2+sqrt5 and 2-sqrt5, and this can be rewritten as [4±√20]/2.

By equating these, we get that -b = 4 and b² - 4c = 20.

From the first equation, b = -4. Substituting this into the second equation gets 16 - 4c = 20 and hence c = -1.

Therefore, the quadratic equation that gives these roots is x² - 4x - 1 = 0.

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