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#1 2007-01-15 15:22:21
- jxharmon
- Member
- Registered: 2007-01-08
- Posts: 104
Find a solution for the equation
find the ordered pairs for the following:
3x = 4y = 12
(0,3)
(?, 3/4)
(4,0)
8/3, ?)
For some reason the fractions are stumping me...any easy way to work this?
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#2 2007-01-15 17:38:27
- pi man
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- Registered: 2006-07-06
- Posts: 251
Re: Find a solution for the equation
First of all, I think that should be 3x + 4y = 12. The first pair is (0,3). Plug in 0 for x and 3 for y and see if the equation is true. 3(0) + 4(3) = 12. Yep.
For the second one, plug in 3/4 for Y and solve for X.
3x + 4y = 12
3x + 4(3/4) = 12
3x + 3 = 12
3x = 9
x = 3
So that give you (3, 3/4)
Do something similar for the last one:
3x + 4y = 12
3 (8/3) + 4y = 12
8 + 4y = 12
4y = 4
y = 1
So: (8/3, 1)
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#3 2007-01-16 09:53:47
- jxharmon
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- Registered: 2007-01-08
- Posts: 104
Re: Find a solution for the equation
thank u.
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#4 2007-01-16 11:03:20
- jxharmon
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- Registered: 2007-01-08
- Posts: 104
Re: Find a solution for the equation
What about something like...
y = 3/4x + 2
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#5 2007-01-16 21:59:11
- Snow
- Guest
Re: Find a solution for the equation
I think the way that formula works "3x=4y=12" as you have given it wouldn't allow the formula to be like that. It would look like this, y=-3/4+3 which puts it into linear equation form.
#6 2007-01-17 12:27:51
- Stanley_Marsh
- Member
- Registered: 2006-12-13
- Posts: 345
Re: Find a solution for the equation
divide both side by 4 , we have 3/4x+y=3 , then x must be in this form of integer , x=4n ,n can be 1,2,3,4,5....... , then the equation becomes 3n+y=3 , n and y can be anything thing ~infinte solution.
Numbers are the essence of the Universe
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