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**Equation ?**

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**jxharmon****Member**- Registered: 2007-01-08
- Posts: 104

How do I write an equation of the line with slope -2 and y-intercept (0,0)?

would it be

y=-2x or y= x -2

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

The first one is correct. The slope determines the coefficient that goes before the x term and the y-intercept determines the constant term.

Basically, a line with slope a and y-intercept (0,b) will have the equation y = ax+b.

Why did the vector cross the road?

It wanted to be normal.

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**littlelittle****Member**- Registered: 2007-01-24
- Posts: 10

Hi

How did you solve this problem. Can you explain it stepwise pl.

Thanks

S

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**Monox D. I-Fly****Member**- Registered: 2015-12-02
- Posts: 755

littlelittle wrote:

Hi

How did you solve this problem. Can you explain it stepwise pl.

Thanks

S

It's just as mathyperson said.

Since the line in question has slope -2 and y-intercept (0,0), so a = -2 and b = 0. Substitute them to the y = ax + b equation and you have:

y = ax + b

y = -2x + 0

y = -2x

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**Equation ?**