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sorry to bother you again!
I need help with two questions on series..
1. Find the range of values for which the following series is convergent or divergent:
2. Investigate the convergence of the series
forHope you can help. Thanks
#2.) This was really hard for my BASIC program I wrote because of rounding errors.
The best I could come up with is that at 0.9999, you get 10.34 or something.
And at 0.99995 it started to grow, so maybe that means at 1 it goes to infinity.
If I have time, I'll try to program this with a better precision program. Sorry.
So the answer just might be convergence of 10.33 at about .999999, not sure...
igloo myrtilles fourmis
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1) |x|<1 convergent, |x|>1 divergent-an 1.0001^n series go larger and larger than n^3 series sooner or later. x=1 or x=-1 case, by evaluating them in the series formula we know convergence.
So the convergence interval is [-1,1]
X'(y-Xβ)=0
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thanks for your replys guys
2. John, you're right.
for |x|<=1 the second coverages, and it's:
Last edited by krassi_holmz (2007-02-03 21:55:58)
IPBLE: Increasing Performance By Lowering Expectations.
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