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#1 2007-02-20 06:13:30

Kiran
Member
Registered: 2006-11-15
Posts: 177

Expandiing

ab/m ( -2m^(-2) / ba  +  3m / a^(-1) b  )

than

ab/m (-2/abm^(2) +  3am/b) < handle negative exponents
ab/m * -2/abm^2 + ab/m * 3am/b < distribute
now i have to do......


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#2 2007-02-20 16:27:32

ganesh
Administrator
Registered: 2005-06-28
Posts: 32,581

Re: Expandiing

Kiran,
If the question was simplifying the expression
ab/m ( -2m^(-2) / ba  +  3m / a^(-1) b  ),
the steps would be
ab/m ( -2m^(-2) / ba  +  3m / a^(-1) b  )
= ab/m[-2/bam²+3am/b]
=[-2ab/bam³+3a²bm/bm]
=-2/m³+3a²
(Cancelling the common factors in the numberators and the denominators)
-2/m³+3a² cannot be simplified any further.


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