Math Is Fun Forum

Identity

Member

Registered: 2007-04-18

Posts: 934

Check please

Graphs y = mx and y = 6 - mx are drawn. The intersection of the two lines is M.

Find, in terms of m, the x-intercept of the graph with equation y = 6 -mx
0 = 6 - mx
mx = 6
x = 6/m
so (6/m, 0)

Find in terms of m, the coordinates of the point of intersection of the two graphs.
mx = 6 - mx
2mx = 6
x = 6/(2m)
x=3/m
y=3
Hence: (3/m, 3)

Find the area, in terms of m, of triangle OMN
OMN = 1/2(6/m*3) = 1/2(18/m) = 9/m units^2

Find the value of m when the are of the triangle OMN is 6sqrt(3). Express your answer in simplest form with a rational denominator

George,Y

Member

Registered: 2006-03-12

Posts: 1,379

Re: Check please

9/|m| instead of 9/m
|m|=√3/2 so m has two possibilities.

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