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#1 2007-08-10 04:45:29

misdamike55
Member
Registered: 2007-08-10
Posts: 1

in need of help

Z Is A Standard Normal Random Variable
How Do You Do This One
P(z>-2.08)

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#2 2007-08-10 05:55:38

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: in need of help

P(Z>-2.08) = P(Z<2.08).

You can look up that second expression in a table of Z-values.


Why did the vector cross the road?
It wanted to be normal.

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#3 2007-08-10 06:10:20

misdamike55
Member
Registered: 2007-08-10
Posts: 1

Re: in need of help

its that easy

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#4 2007-08-10 10:33:35

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,711

Re: in need of help


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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#5 2007-08-10 22:34:25

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: in need of help

That's interesting. The tables I've seen before give probabilities of Z ≤ x, where x is some positive number.

Your one gives P (0 ≤ Z ≤ x) instead. Your way is probably a bit more useful, actually.


Why did the vector cross the road?
It wanted to be normal.

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