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ABCD a parallelogram and BCED a cyclic quadrilateral , AN stret line cut interior segment CD in M and stret line BC in N ,let ME=NE=CE
show that the m(angle) betwen AN and CE = 90°
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What's a stret line? cut CD in half at M?
cut CD into M parts?
I read about four points on a circle make a polygon.
Also cyclic triangles have formulas that might help.
igloo myrtilles fourmis
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Consider five points A, B, C, D and E such that ABCD is a
parallelogram and BCED is a cyclic quadrilateral. Let ℓ be a line passing
through A. Suppose that ℓ intersects the interior of the segment DC at F
and intersects line BC at G. Suppose also that EF = EG = EC. Prove
that ℓ is the bisector of angle DAB
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