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#1 2007-09-13 08:29:46
- Sharlyne
- Guest
Need Help Pleaseeee!!!!
Ok Could someone please help me, ill be more than grateful, heres the question:
1. The function f is defined for all real values of x by f(x )=e^3(x+2)
a) describe geometrically a series of transformations whereby the graph of y = f(x ) can be obtained from the graph of y=e^x
#2 2007-09-13 14:14:52
- John E. Franklin
- Member
- Registered: 2005-08-29
- Posts: 3,588
Re: Need Help Pleaseeee!!!!
I'm gonna assume e^(3(x+2)) is what you mean,
but ignore if I'm wrong.
Now just cube e^x for any x, and multiply by 403 or so.
403 is inverse ln of 6.
403.428... Try it on calculator.
igloo myrtilles fourmis
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#3 2007-09-13 21:11:48
- mathsyperson
- Moderator
- Registered: 2005-06-22
- Posts: 4,900
Re: Need Help Pleaseeee!!!!
First draw y=e^x. Then move it two units to the left.
Finally, enlarge it along the x-axis with a scale factor of 1/3.
Why did the vector cross the road?
It wanted to be normal.
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#4 2007-09-14 03:29:06
- rph105
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- Registered: 2007-09-13
- Posts: 1
Re: Need Help Pleaseeee!!!!
First draw y=e^x. Then move it two units to the left.
Finally, enlarge it along the x-axis with a scale factor of 1/3.
thank you, but why the scale factor a 1/3
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#5 2007-09-14 05:16:51
- mathsyperson
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- Registered: 2005-06-22
- Posts: 4,900
Re: Need Help Pleaseeee!!!!
Because the graph reaches values faster as a result of the function being multiplied by 3.
For example, e^x would equal e when x=1, but e^3x is e at x=1/3.
Why did the vector cross the road?
It wanted to be normal.
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