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#1 2007-09-19 08:25:24

sheik_master
Guest

equivalent equations

ahhh



2^2x - 33(2^x) + 32 = 0




5^x^2 (625) = (1/25)^2x


help??:)

#2 2007-09-19 08:31:33

sheik_master
Guest

Re: equivalent equations

or it can go like this:



1)      2²ª – 33(2ª) + 32 = 0
   

           ²
2)     5ª (625) = ( 1 )²ª
                  25


The second one is five to the power of "a" squared.....and it equals bracket one over 25 bracket, all to the power of 2a



lol thanks

#3 2007-09-19 08:41:37

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: equivalent equations

1)  a = 0 is one possibility

2) I don't know what order to do the power in (5^x)^2, or is it 5^(x^2) ?

Last edited by John E. Franklin (2007-09-19 08:44:01)


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#4 2007-09-19 08:45:10

sheik_master
Guest

Re: equivalent equations

John E. Franklin wrote:

1)  a = 0 is one possibility

2) I don't know what order to do the power in (5^x)^2, or is it 5^(x^2) ?

Im not sure either...

I only have written here 5^x^2 .....

#5 2007-09-19 08:59:03

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: equivalent equations

(1)

Let x = 2[sup]a[/sup].

Then your equation is x² - 33x + 32 = 0.
(x-32)(x-1) = 0
x= 32 or 1.

Substituting back, 2[sup]a[/sup] is 0 when x=1, and 5 when x=32.
So your two answers are 1 and 5.


Why did the vector cross the road?
It wanted to be normal.

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#6 2007-09-19 13:51:48

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: equivalent equations

On the last problem, I tried -2 and it works if
you square the -2 first in the power and then do the 5 up 4.
So (5^(-2^2) )(625) = (1/25)^-4


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