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#1 2008-02-18 13:11:17
- LuisRodg
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- Registered: 2007-10-23
- Posts: 322
How would one go to solve this integral?
If you have:
Last edited by LuisRodg (2008-02-18 13:11:46)
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#2 2008-02-18 19:53:29
- Identity
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- Registered: 2007-04-18
- Posts: 934
Re: How would one go to solve this integral?
Use partial fractions:
Now use a linear u-substitution on the first fraction and the other two fractions are easy.
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#3 2008-02-19 08:29:36
- LuisRodg
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- Registered: 2007-10-23
- Posts: 322
Re: How would one go to solve this integral?
We havent got to partial fractions. Thats next section. We are supposed to solve it without partial fractions?
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#4 2008-02-19 08:50:27
- mathsyperson
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- Registered: 2005-06-22
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Re: How would one go to solve this integral?
That's not really partial fractions though. You split a fraction into two partial fractions if the denominator has a higher order than the numerator.
What's happening here is you're just factoring out whole numbers and leaving a constant as the numerator of your fraction (thus making it integrable).
Why did the vector cross the road?
It wanted to be normal.
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