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#1 2008-02-25 05:21:14

frem
Member
Registered: 2008-02-23
Posts: 3

confusing...

I've answered an exact equation. The question is:
(x-y³ +y² sinx) dx = (3xy²+2y cosx) dy = 0.
In the end, I got (x²/2)-y²  cosx - y³x=C but the answer in the answer sheet is opposite sign to my answer. Does my answer can be accepted?

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#2 2008-02-27 03:02:04

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: confusing...

I would say so. Multiplying both side of what you have by -1 gives [Their LHS] = -C.
But C is an arbitrary constant, so changing its sign doesn't alter that it's an arbitrary constant.
So you could just as easily write [Their LHS] = C.

So your answer is equivalent to the one they give.


Why did the vector cross the road?
It wanted to be normal.

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