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27x^2-12y^2
(x-y)^2-4(p-q)^2
There's no obvious way to factorise those that I can see.
You could partially use difference of two squares on the first one, to get:
15x^2 + 12(x+y)(x-y)
Or even 3[5x^2 + 4(x+y)(x-y)]
But I wouldn't say that's particularly better.
I'm fairly certain that the second one is as simple as it can get too.
Why did the vector cross the road?
It wanted to be normal.
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Nice Joke up there... Mathsy!
:-)
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