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#1 2009-03-11 03:47:02
- StatsStudent
- Guest
Permutation Question
If eight cards are selected WITH replacement from a standard pack of 52 cards, where there are 12 picture cards, 20 odd-numbered cards and 20 even-numbered cards. How many sequences will contain 3 picture cards, 3 off-numbered cards and 2 even-numbered cards?
I have figured out that there are 52^8 = 5.346x10^13 different sequences. I just can't figure out how to get the answer for the question.
Would it not be 12^3x20^3x20^2 = 5.5296x10^9?
#2 2009-03-11 07:10:23
- JaneFairfax
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- Registered: 2007-02-23
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Re: Permutation Question
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#3 2009-03-11 07:39:58
- StatsStudent
- Guest
Re: Permutation Question
Ah I see, thank you.
#4 2009-03-11 07:48:45
- mathsyperson
- Moderator
- Registered: 2005-06-22
- Posts: 4,900
Re: Permutation Question
I think that formula counts sequences with repeated cards more than once.
Correcting it would be messy though, since a compensating term would have a similar problem, in that it would overcount sequences with more than one repeat.
Why did the vector cross the road?
It wanted to be normal.
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