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#1 2009-03-22 13:37:09

MarkusD
Member
Registered: 2006-10-08
Posts: 28

Joint Probability and Independence

Can someone explain to me why the first is independent and the 2nd is not?

Given the joint probability distribution check if the following is independent:

f(x,y)= 1/4 for:

x=-1, y=-1;
x=-1, y=1;
x=1, y=-1;
x=1, y=1


The example of nonindependence is:

f(x,y)=1/3 for:

x=0, y=0;
x=0, y=1;
x=1, y=1

but Im not sure how one is indenpendent and one isnt when my book just says the def of independence is: f(x1...xn)=f1(x1)*....fn(xn). Any help?

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#2 2009-03-24 15:20:20

MarkusD
Member
Registered: 2006-10-08
Posts: 28

Re: Joint Probability and Independence

Anyone?

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