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hi i'd like to know how to calculate by Taylor's series the n-th derivative term from a function.. Example i've the
and i for example the term 2006 with x=0:
help me
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you should be able to get an expression for the nth derivitive:
the bottom of the fraction is simple, the top follows the pattern:
1 -> 2 x 1
2 -> 2x2 x 1
3 -> 2x2x2 x 1x2
4 -> 2x2x2x2 x 1x2x3
5 -> 2x2x2x2x2 x 1x2x3x4
6 -> 2x2x2x2x2x2 x 1x2x3x4x5
n -> 2^n(n-1)!
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if you are instead allowed to use the mclaurin series for ln(1-x) then you have:
then:
which gives you:
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in either case (using windows calculator)
Last edited by luca-deltodesco (2009-04-21 23:32:18)
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thanks man, that's it xD
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