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Hey - I'm a little stuck on some of these questions. I would really appreciate it if you led me in the right direction - thank you. ^_____^
Firstly.
I have the cubic equation x³+ax+b=0, where and a b are constants, and has roots α, β and γ.
I know that a=αβ+βγ+αγ and that b=-αβγ
It tells me that αβ=γ and to express a and b in terms of γ only.
I can get b=-γ²
But I can't find a. I keep of getting more and more α's and β's.
I can get a down to: a=γ+γ(α+β) But then I get stuck. >_<
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Secondly.
I have 3 simultaneous equations:
-x+2y+z=a
x+y+z=b
4x+y+2z=c
And I know that the determinant is 0 and so it has no unique solution. But what I am asked to find is the relation between a,b and c for which the equations are consistent. And I have no idea how to do that. o_O
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Thirdly.
I have a point P with column matrix
I found that the column matrix of Q would be:
And then I need to show that the line joining P to Q makes and angle θ with the x-axis. I can do it numerically, but not algebraically. What would be the algebraic method?
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And that's it. ^_^ Thank you very very much for your help in advance. It will be greatly appreciated.
You can find another relationship between α, β and γ by equating coefficients of the x² term of the equation. That will allow you to express α+β in terms of γ and so you'll be done.
Your three simultaneous equations have a determinant of 0 because the first two have LHS's that can be combined in some way to form the LHS of the third one.
ie. m(-x+2y+z) + n(x+y+z) = 4x+y+2z, for some value of m and n.
Find those and the relationship between a, b and c will follow.
Why did the vector cross the road?
It wanted to be normal.
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Oh yes. >_< Gah, how did I forget that? Haha, okay, I've got the first question down.
Is it really that easy? I thought that it would have been like that because I remember reading that they had to be multiples of each other. It is worth 4 marks. But okay, I will use that method. Thank you. ^_^
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