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Two cards are simultaneously drawn from an ordinary deck. The probability that they're not both the same suit is? Thanks!
Hi karney;
First card could be any card out of 52
Second card 39 out of the 51 remaining
Last edited by bobbym (2009-05-27 12:37:52)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Where do you get the 39/51?
Thanks...
Hi JoAnni;
After you have picked some card there are 51 left and 12 of the same suit as the card you already picked. You don't want any of those 12, so there are 39 (51-12=39) that are not of the same suit.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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