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Hi I need help fiding derivative of inverse using this rule : f-¹ = 1/ f'[f^-1(x)]
1. f(x) = √2x, x ≥ 0
Find derivative of inverse using f-¹ = 1/ f'[f^-1(x)]
2. f(x) 2x²-2, x ≥ 0
Find d/dx f^-1 (0) [Note that f(1)=0
Please help me solve BOTH problems using THIS RULE =====> f-¹ = 1/ f'[f^-1(x)]
Also, Please explain how you did it.. Thnaks
Hi makaros;
For 1)
If you meant f(x)=√ (2x) then this is how I do it.
Last edited by bobbym (2009-07-19 13:09:27)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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