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Hi;
How did you go about getting this integral?
This one is a little too difficult for right now (turns out it equals arctan(x)) Are you sure you have the right problem? Did you mean
Last edited by bobbym (2009-08-04 07:06:13)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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The above integration is tan^-1 x +C
Correct?
Well the problem is:
0
∫ 2/(1+x^2) dx
-1
Okay then we have the 4 things we need for an IBP
Now using the formula:
Now with the intervals of integration of -1 , 0
Last edited by bobbym (2009-08-04 07:48:17)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Correct it the right answer...
Your very good at math, )))
Mostly I understand how to do U substitution but once I see a fraction I dont know how to do it..
(((
Hi Makaros;
I am passable on a good day at maths and sometimes I get lucky. Glad to help a little.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Oh here, I got one more question,
Find
2
∫ (x+1) dx
-2
How to solve it?
Math,can be hard sometimes but your will get it,just keep trying.:)
Hi Makaros;
Last edited by bobbym (2009-08-04 08:03:19)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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OK, taht is also correct)
how about this one:
∫ x^3 e^(-x^2/2) dx Note: -x to the square of 2 all devided by 2, NOT including e
It says At first I gotta use Substitution rule AND than IBP
Hi Makaros;
For:
Use the substitution;
The new integral is:
Now use IBP.
Last edited by bobbym (2009-08-04 08:54:52)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi, Can you expalin briefly how you got that new integral, step by step.
Hi;
Use the substitution;
Now replace the x^2/2 with u
Now an x dx with a du
and an x^2 with a 2u
Now use IBP
Last edited by bobbym (2009-08-04 09:07:44)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Ok, but where do you get x^2 = 2u ???
Hi Makaros;
Solve for x^2 from this.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I get
(√u)/2 =x
Hi;
Now times both sides by 2.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Ok I get it not, may you continue witH IBP
Hi. do you mind helpig me with one more question. I truly got lost on that one.
∫ e^(√x)
It says I gott to find an appropirate substitution and than use IBP.
Would sooo appreciate it.
Hi Makaros;
For the integral
Say:
The new integral is:
An easy one for IBP.
Last edited by bobbym (2009-08-04 12:41:37)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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