Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2009-09-03 15:10:37

diamondeyes
Member
Registered: 2009-09-03
Posts: 2

find derivative of inverse sin(sqrt(2t)) PLLLLLZ HEEELLP!

the problem says to find the derivative of inverse sin(sqrt(2t)).
I know the general equation for inverse sin(u)= (1/sqrt(1-u^2))(du/dx).
im having a hard time first finding the derivative of sqrt(2t). i know the chain rule and power rule is used but i dont know how.

Offline

#2 2009-09-03 17:30:18

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: find derivative of inverse sin(sqrt(2t)) PLLLLLZ HEEELLP!

Hi diamondeyes;

You have

Say:

Now you have

By the chain rule:

So all you need now is:

and

and then you just plug those two derivatives into the chain rule. Can you take it from here? If not, take a peek.

Last edited by bobbym (2009-09-03 22:27:39)


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

Offline

Board footer

Powered by FluxBB