Need Math grade 10! Help. Complement and Synthesis.

cluelessinmath · 2010-01-12 16:04:08

P.S. This is just for information purposes.
I talked to someone, about #2 and they came up with a theory that it might be connected with #1, do you think that is plausible?

bobbym · 2010-01-12 16:13:36

Hi;

I am not sure about #9 yet. I don't think #1 and #2 are related.

cluelessinmath · 2010-01-12 16:20:58

OK, like I said it was just a theory. I guess I will relax for tonight, so I will see you tomorrow with a bit more questions left and then I will stop abusing your mathematical mind, which helped me out a lot today. Thank you very much, for all that you have done for me, I have a bit more left and then I shall be done.

Well if you don't see me tonight, then Have a good day, a good evening and a good night.

bobbym · 2010-01-12 17:10:49

Hi;

I think I see that you have a couple of misconceptions and it is time for a good rant.

cluelessinmath wrote:

I failed to do because of minor mistake that I did not take into consideration.

If there is any worse falsehood then the way the modern school sytem trains it's students to believe the above quote. There are no small errors! Example: a student works through a tough calculus problem, he solves it. At the end he plugs 3 into x^2 + 5 and gets 12 instead of the correct 14. The teacher says well you showed the work and you only made a slight arithmetic error on the end so I will grade you a 9 out 10 for that question. Well in the real world that rocket ship hurtling towards the moon doesn't give a hoot where you make your mistake, it's going to explode killing everybody aboard. Nothing is crippling students more than the notion of partial credit. I can't tell you the trouble I have been in because of so called tiny errors. Errors that I still make routinely.

cluelessinmath wrote:

I get your insight and finalize this horrendous test

The test is not horrendous because math is beautiful. It is an art form.

Bricklaying can be great if a guy knows what he is doing and why - Fast Eddie Felson

Like art and music and chess and many other things it is a sublime experience. I am trying to pass some of that from me to you. Math is not a test or a chore, it is a religious experience, an enlightenment. If you let it touch your soul you won't need my insight, rather I will need yours.

cluelessinmath · 2010-01-13 01:04:21

Well I can see what you mean. The thing is that as soon as I'm done with this last book, I can finally get to college since my prerequisites will finally be done with. I wasn't created in this life time to be a scientist, or some great mathematician. My path is different.

To me as long as I know the basics that I would need to survive with, would do me just fine. But what you have done for the past day, has helped me out more in this book than the last semester wasted with a teacher who doesn't give a hoot about how we learn just as long as we get out of her class ASAP. Which I find very disappointing.

Well I'm off to school for today so I will see you later this evening, and hopefully finish off these questions. I have 5 more numbers to go, and in the same time the ones we went through together yesterday, which I will post my answers and you can correct my mistakes so I have a better understanding.

cluelessinmath · 2010-01-13 01:09:58

P.S. If you can take a look at #9 before I come back so that we can start off there right away. It would be very generous of you. I will go ahead and post the other 3 numbers right now so that maybe you can take a look at these as well while I'm not there. I have provided the answers with them, so If you can look them over and tell me if there is any mistakes and how to fix them as well. Thank you in advance and I'll see you later today.

11. A manufacturer packages Styrofoam balls in two similar boxes of different sizes.
The smaller box is 90 cm high and the area of its base is 360 cm2(squared).
The area of the base of the larger box is 640cm2(squared).

A worker in the company maintains that the larger box can hold at least twice as many Styrofoam balls as the smaller box.
Check whether or not his claim is correct. Show Work!

My Answer:

640/360= 64/36= 16/9= 1.7
His claim is incorrect. The box can hold 1.7 times more balls then the small one.

Please if this is correct then do say it. If it's not then what should the right answer be?

12. A garden is rectangular in shape.
One of the sides of the garden is 12 meters long and forms an angle of 23*(degrees) with one of the diagonals.
The garden will be reshaped into a square that will be equivalent to the current rectangular garden.

http://i206.photobucket.com/albums/bb308/missy_me420/math12.jpg

Given that the current garden is enclosed by a fence.
Determine whether this fence will be long enough to enclose the square garden.
Round off your answer to the nearest unit. Show Work!

My answer:

Tan 23o(degrees)= 9/12
0.4245*12= 5.09 m

area of rectangle= 12*5.09= 61.08 m2(square)

area of new square= √61.08= 7.82(side)

Two sides would have to be shortened and two sides would have to be increased.

Please if this is correct then do say it. If it's not then what should the right answer be?

13. A company sells products in cylindrical containers 16 cm high.
To make transport easier, the company decides to modify the dimensions of the containers,
while keeping them equivalent to the original containers.
The height of the new containers will be increased by 9 cm,
and the radius of the base will be decreased by 5 cm.

If the label covers the entire surface of the cylinder,
what will be the area covered by the label on the new container?
Round off your answer to the nearest unit. Show Work!

My Answer:

2*(3.14)*(x-5)*25= 2*(3.14)*x*16= 157.07x-785.4= 100.53x
157.07x-100.53x= 785.4
56.54x=785.4
x=13.89= r

2*(Pie=3.14)*(13.89-5)*25= 1396.44 cm2(square)

Please if this is correct then do say it. If it's not then what should the right answer be?

Thanks again, and I'll see you shortly.

bobbym · 2010-01-13 03:38:11

Hi;

#9 is correct except when you get the distances of the line segments AB and CD do not be in sych a hurry to convert to decimal. What would you have done if you didn't have your calculator handy?

AB =√116 = √(4 * 39) = √4 * √39 = 2*√39
CD =√116 = √(4 * 39) = √4 * √39 = 2*√39

Easy to see that those 2 sides are equal.

bobbym · 2010-01-13 03:47:31

Hi;

cluelessinmath wrote:

I wasn't created in this life time to be a scientist, or some great mathematician. My path is different.

So you have been training with Obi Wan Kenobi, you know your path... It is your decision of course but don't be so sure. I have worked in a meat plant, a cemetary and a car rental, I was a supervisor for Otis Elevator, a dealer, a floorman. a card counter, a would be writer, freelance programmer, a professional bowler, a professional poker player, and I worked at an certain facility here in Nevada.

And I am not decided yet!

#11 is correct provided that the bigger box is also 90 cm tall. The problem doesn't say. Except it says they are similar this has a particular meaning in geometry. It would imply that the height is also in proportion and larger than 90 cm. In which case it might hold twice as many balls. Please check you work.

#12 You haven't figured the perimeter of both yards, then you can answer the question as to whether their is enough fence.

cluelessinmath · 2010-01-13 10:36:12

Thank you for the reply.

Would it be possible, for you to give me the detailed calculations that you used to solve #11,#12,#13?
In order for me to understand it a bit better. It would be easier for me to understand the mathematical equation more, If I was to have the calculations. Like that I could compare mine with yours.

Thank you.

bobbym · 2010-01-13 14:30:03

Hi;

Whoa! We still have #13 to do!

13. A company sells products in cylindrical containers 16 cm high.
To make transport easier, the company decides to modify the dimensions of the containers,
while keeping them equivalent to the original containers.
The height of the new containers will be increased by 9 cm,
and the radius of the base will be decreased by 5 cm.
If the label covers the entire surface of the cylinder,
what will be the area covered by the label on the new container?
Round off your answer to the nearest unit. Show Work!

Remember V = π r^2 h

I will tell you how I interpret the problem. I am assuming that when the company says equivalent they mean the same volume. We start with a cylinder that has volume V1. It is defined by:

The company wants to make an equivalent volume with a new container that has volume V2 it is defined by:

We don't know what r is, but we can solve for it by making use of the fact that V1=V2

We of course get 2 answers: r = 25 / 9 and r = 25. We reject r = 25 / 9 because it is nonsensical. So r =25. Now we are ready to do the second part of the question. The label part. I am assuming that the lable only covers the sides of the cans. Have you ever seen a label that covered the sides and the lids? Of course not.

The area of the side of a cylinder (can) is:

The first can had a r of 25 cm and a h of 16 cm and the lable completely covered the side. So the label has an area of

The second can has an r of 20 cm and an h of 25 cm. So it has a side area of:

So even though the two cans have the same volume the label on the first can only covers 4 / 5 of the surface of the second can.

cluelessinmath · 2010-01-14 03:13:26

Thank you very much, I realized where my mistake was but my reasoning was correct by interpreting the problem.

Now I understand better when you explain to me with equations, it helps me realize not to make the same mistakes anymore and it gives me even a better understanding of the problem.

So if you have the chance to do the same with number #11 and #12. I would see better where I'm at fault.

P.S. Sorry that I wasn't on last night, I had a long school day, I just passed out when I got home. Later on today I will post my answers for number #7, #8 and #9 so that we can verify them more in depth.

Thanks alot, talk to you soon.

cluelessinmath · 2010-01-14 03:17:50

P.P.S. Also if you can take a look back at #1, I solved it but I don't get it can that actually be the answer or not, because it makes no sense to me. Because when you use the calculations it gives you in the end of it all -0.4 etc... Which in this case it gives me a negative and thus comes out to saying that it has no zeros. Can this be the plausible answer? Or did I do something wrong?

bobbym · 2010-01-14 04:35:44

Hi;

I solved #1 in post #2, please indicate what you don't understand about the solution.

bobbym · 2010-01-14 05:08:22

I have to mention the fact that you are posting these exact questions on another forum. My time is valuable to me, I don't care for posting games.

http://www.mymathforum.com/viewtopic.php?f=13&t=11775

I do not know whom you first posted to. I passed up a more difficult question because I thought you needed help, I had no idea you already have the answers. You said you wanted detailed solutions and I assumed that you were interested in thoroughness,

I do not like that you only wanted detailed solutions so my answers could be scrutinized. Who is learning here? Why are my conclusions being examined and not yours? I am a member of that forum too. I do not like having my work judged clandestinely. Please refrain from posting elsewhere the same problems or use him exclusively.

cluelessinmath · 2010-01-14 08:33:15

The reason being for multiposting on both sites, is because I want to come up to the same conclusions on both ends. I presume having more heads helping me out with the same problems, which gives me a better advantage in understanding how to solve these questions with multiple techniques.

You might give me a way how to solve it, and maybe the other person might have an easier way of doing the same problem. Or you might not be able to verify a number because there might be some facts missing and the other person might see all of the facts present and can solve it. So I'm not choosing sides here if that is what you mean. Since this is my final book and the exam will be based almost similarly as this pretest, which will be next week for me.

That is why I am trying to get all the calculations for each number, and detailed explanations from both parties, in order to choose the most logical answers and thus understand my mistakes so that I can rectify them as quickly as possible and not repeat them.

I'm sorry if you feel like I offended you in any way, this was clearly not my intention. I just want, help from both sides and in order to compare my calculations to both of yours in order to see the logic and errors I have done.

If need be, I will not post anything on the other site anymore and just do everything just with you.

Thanks again, for your time and reasoning.

bobbym · 2010-01-15 03:31:37

If need be, I will not post anything on the other site anymore and just do everything just with you.

And what about his feelings? Do you imagine he is made out of cardboard? You are choosing sides and it should not have come to this. I am sure he will read this post. He gets around you know. Hasn't he done a lot of work too! He is a good problem solver and a good man. You must consider your actions before doing them.

cluelessinmath · 2010-01-15 05:00:44

I'm sorry if I have done wrong to both of you. This wasn't my intention. I just wanted to get help, insight, input, answers, from as much people as possible. So that if all agree on the same answers it would help me out in solving the problems efficiently, thoroughly, and properly with less confusion as possible.

If you do not want to help me out anymore, than I understand and I will not post anything anymore on this site and the other one as well. All you need to do is say STOP and I won't bother you both anymore.

I would like to thank both of you for all the help you gave me and the time you took in me.

So would I be able to continue to post here and get your help, or no?

bobbym · 2010-01-15 05:17:23

Hi;

Yes.

cluelessinmath · 2010-01-15 06:05:56

Like I said, I'm sorry if I offended you in any kind of way. I will refrain on posting the same questions on both sites, since there is little left, I will then just finish the rest of the numbers with you Bobby. And then when it will be finished, I will be out of your way as swiftly as the wind.

Once I shall do my exam next week, I will keep you posted with my results and then I will close this thread with a Thank you letter.

OK! #13, #10, #9, #8, #5, #4, #3 are done and I understand them. Thank you.

#1,#2, #6, #7,#11, #12. Are the ones left. I will post the answers I got tonight, and then we will take it from there.

Math Is Fun Forum

#26 2010-01-12 16:04:08

Re: Need Math grade 10! Help. Complement and Synthesis.

#27 2010-01-12 16:13:36

Re: Need Math grade 10! Help. Complement and Synthesis.

#28 2010-01-12 16:20:58

Re: Need Math grade 10! Help. Complement and Synthesis.

#29 2010-01-12 17:10:49

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#30 2010-01-13 01:04:21

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#31 2010-01-13 01:09:58

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#32 2010-01-13 03:38:11

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#33 2010-01-13 03:47:31

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#34 2010-01-13 10:36:12

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#35 2010-01-13 14:30:03

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#36 2010-01-14 03:13:26

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#37 2010-01-14 03:17:50

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#38 2010-01-14 04:35:44

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#39 2010-01-14 05:08:22

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#40 2010-01-14 08:33:15

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#41 2010-01-15 03:31:37

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#42 2010-01-15 05:00:44

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#43 2010-01-15 05:17:23

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#44 2010-01-15 06:05:56

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