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#1 2010-01-26 05:15:17

zoolanderman2
Guest

Solving equation...

x³ + 4x² = 0

How to solve this.....? please help, thank you!!

#2 2010-01-26 05:23:25

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: Solving equation...

See how x³ is the same thing as x² times x.
You can use this information to factor the equation:
x²x + 4x² = 0
Take the x² out to the left:
x² ( x + 4 ) = 0
From this you can see that x = -4 will make it all zero, so that's one answer.
And x=0 will make the x² be zero, so that is another answer.

I should like to see a graph of this...


igloo myrtilles fourmis

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#3 2010-01-26 05:33:11

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: Solving equation...

Oh, about graphing it, you kind of need to have a "y" in place of the zero to graph it.
Like:
y = x³ + 4x²

When y is zero, that is the x-axis, where the curvy graph crosses at -4 or touches at zero, on
the x-axis.


igloo myrtilles fourmis

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#4 2010-01-26 05:38:37

zoolanderman2
Guest

Re: Solving equation...

Dude i'm so sorry it should be x³ + 4x² = 100 not 0 sad

sorry for wasting your time, but how do i do x³ + 4x² = 100?

#5 2010-01-26 05:41:45

zoolanderman2
Guest

Re: Solving equation...

it says x is between 3 and 4. how do i do this without using trail and improvement

#6 2010-01-26 05:48:00

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: Solving equation...

Okay, I'll cut and paste my above solution and change the numbers.
See how x³ is the same thing as x² times x.
You can use this information to factor the equation:
x²x + 4x² = 100
Take the x² out to the left:
x² ( x + 4 ) = 100
From this you can see that x = ???? will make it 100.
Woops, this is harder!!
How about guess 3 and a half?
3.5 times 3.5 is 12.25 and (3.5 + 4) times that is 12.25 times 7.5, which is 91.875, pretty close!
Go higher...
Guess 3.6
3.6 times 3.6 is 12.96 and (3.6 + 4) times that is 12.96 times 7.6, which is 98.496, getting closer!!

3.62212 is very very close!

Last edited by John E. Franklin (2010-01-26 05:52:15)


igloo myrtilles fourmis

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#7 2010-01-26 05:50:20

zoolanderman2
Guest

Re: Solving equation...

it's 3.622, but i want to know how to get that without using trial and improvement...

#8 2010-01-26 06:04:52

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: Solving equation...

Click on the picture below
to enlarge.  It shows a
formula from wikipedia
that is a last resort, instead
of a cubic method.


igloo myrtilles fourmis

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#9 2010-01-26 06:10:03

zoolanderman2
Guest

Re: Solving equation...

hi John.....thanks for the formula! my worry now is that i cant even write that in the space that i have to show my working, lol. what was the cubic method you said? i think i am supposed to factorise, or use another method. thanks ^^

(my teacher said none of the ques. are supposed to use the cubic formula)

thanks!

#10 2010-01-26 06:28:55

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: Solving equation...

You've got me stumped now!
Here is something fun to read off the net:

If the formula for the general cubic equation (with no missing terms) is
determined from the (simpler) formula for the cubic equation with no x^2
term, it is seen that the formula for the case of a cubic with no x term is
"a bit simpler" than the formula for the general cubic - but that is still
distinctly more complex than the formula for the cubic with no x^2 term.


igloo myrtilles fourmis

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#11 2010-01-26 12:44:17

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Solving equation...

Hi;

I have run off a computer factorization for you;

For past quadratics, roots are usually gotten by iterative methods that use a computer. In other words interval bisection, secant, Newtons, Jenkins-Traub, Bairstow, Graeffe and a hundred eignevalue algorithms. These are all computer methods.


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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