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taylor_2009

Member

Registered: 2010-01-25

Posts: 28

Find the equation of the tangent line?

Find the equation of the tangent line to the graph x³y^9 = 1 at the point (64, .25) and (64, -.25).

I found the correct equation for the first point, but I can't figure out the second point (64,-.25).

I got y= (1/768)x-(1/3) but mymathlab says that it is wrong.

I also can't figure out this problem.
Suppose that x and y are both differential functions of t and are related by the given equation. Use implicit differentiation with respect to t to determine dy/dt  in terms of x, y and dx/dt

I got dy/dt = (-3x² dx/dt - 3y dx/dt) / (3x-7y^6) but I am not sure if that is right.

Last edited by taylor_2009 (2010-03-16 16:13:31)

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Find the equation of the tangent line?

Hi

I got y= (1/768)x-(1/3) but mymathlab says that it is wrong.

That's what I am getting.

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