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#1 2010-11-07 16:37:28

leadfoot
Member
Registered: 2010-11-05
Posts: 9

Maximum cylinder in a cone

Problem:
Inscribe in a given cone, the height of which is equal to the radius of the base, a cylinder whose volume is a maximum.

This is a calculus maxima problem.  Having drawn a diagram I noticed that


R = b + h or
b = R - h

The generic cylinder volume formula is


Which gives us

After that I did

.  Set
.  Solve for h to get the max volume which does not match the answer of
.

Was I wrong in the initial observation R = b + h ??

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#2 2010-11-07 17:31:54

leadfoot
Member
Registered: 2010-11-05
Posts: 9

Re: Maximum cylinder in a cone

Let me revise my last post.

Working with my previous equation

yielded 
.  A quadratic ewww...

So I decided to solve for the cylinder radius instead with


The V'(h) = 0 did give the correct maxima of
.

Shouldn't the answer workout correctly regardless of whether I solve for the radius or the height?  Why did it work out solving for the radius? How can I know in advance whether to solve for the radius or the height?

Last edited by leadfoot (2010-11-07 17:36:04)

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#3 2010-11-07 19:05:17

TheDude
Member
Registered: 2007-10-23
Posts: 361

Re: Maximum cylinder in a cone

You can get the correct answer by solving for the height, you just aren't being careful with what you're solving for.  When you solved for

you got 2/3 R, which is the radius.  However, if you solved
you probably got 1/3 R, right?  But remember that this answer is in terms of the height of the cylinder.  Remembering that b + h = R, you get b = R - 1/3 R = 2/3 R, which is what you got when you solved for the radius directly.


Wrap it in bacon

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#4 2010-11-08 04:31:20

leadfoot
Member
Registered: 2010-11-05
Posts: 9

Re: Maximum cylinder in a cone

TheDude wrote:

... if you solved

you probably got 1/3 R, right?

I didn't get 1/3 R.

Did I make a math error to arrive at a quadratic?  Is factoring possible without knowing the true value of R?

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#5 2010-11-08 05:34:42

TheDude
Member
Registered: 2007-10-23
Posts: 361

Re: Maximum cylinder in a cone

You know how to use the quadratic formula right?  h is your variable, so a = 3, b = -4R, and c = R^2.  If you solve for this you should get h = 1/3 R.  Although this particular equation is easy to factor too: (3h - R)(h - R) = 0.

Last edited by TheDude (2010-11-08 05:37:10)


Wrap it in bacon

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#6 2010-11-08 08:11:30

leadfoot
Member
Registered: 2010-11-05
Posts: 9

Re: Maximum cylinder in a cone

of course you're right.  i forgot about the quadratic formula.

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