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#1 2011-02-20 01:40:03

Au101
Member
Registered: 2010-12-01
Posts: 353

Differentiation

Hi guys,

I have a question about differentiation, which I'm not quite sure how to set out:

---

The curve C has parametric equations

Find an equation of the tangent to C at A (1,1).

---

Now

And obviously I have a y-coordinate and an x-coordinate.

I'm not so sure about finding the gradient, do I have to let x and y equal 1 and find that t=1?

Last edited by Au101 (2011-02-20 01:40:22)

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#2 2011-02-20 01:58:12

Bob
Administrator
Registered: 2010-06-20
Posts: 10,583

Re: Differentiation

hi Au101,

Nice to hear from you.  How's the study going?

( dy/dx correct btw )

Yes, put t = 1 throughout to get point (1,1) as required and gradient = 2/3.

Then just use y = mx + c to find c.

Bob smile

Last edited by Bob (2011-02-20 02:03:22)


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#3 2011-02-20 02:05:10

Au101
Member
Registered: 2010-12-01
Posts: 353

Re: Differentiation

Hi Bob, it's good to hear from you too.

Okay, so

So do I then discard t=-1 and sub in t=1?

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