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#1 2011-02-28 07:29:28
- wierdling
- Member
- Registered: 2010-11-10
- Posts: 3
logorithims
hi im having problems with sums like log(base)1/2 8 and (log32)/(log8) can some1 plz help me i dont understand this and i keep runing into it.
any help will be gladly acepted
thanx
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#2 2011-02-28 12:00:02
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: logorithims
Hi wierdling;
log(base)1/2 8
You are really saying what power must I raise 1 / 2 to, to get 8. Algebraically we say it like this:
Well 2^3 is 8 so 2^(-3) = 1 / 8. That is your answer.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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