review

zee-f · 2011-08-18 07:18:23

hey am just checking to see if i did these correct,

1. Find the GCF of [3x^3y^5z] and [ 21xy^3z^4].

3x^3y^5z= 3*x*x*x*y*y*y*y*y*z

21xy^3 z^4= 21*x*y*y*y*z*z*z*z

3xy^3z

2. Is sqrt(x) 7 a polynomial? Explain why or why not.

no sqrt(x) 7 is not a polynomial because it has the variable inside a radical.

3. Is x^5 + x^2 + x a polynomial? Explain why or why not.

yes x^5 + x^2 + x is a polynomial because i have coefficients that represent 1 (x's)
and my exponents of 5 and 2 and the third x makes it a trinomial the terms have non-negative integer powers of variables so it makes it a polynomial.

4. What is the degree of x^5 + x^2 + x? How do you know?

the degree of x^5 + x^2 + x is 5 because it's the largest exponents of the variable the degree is five because its the largest exponents of x

5. Simplify (3x^3 + 8x^2 2x + 4) + (6x^2 + 4x + 4).

3x^3+8x^2-2x+4+6x^2+4x+4
3x^3+6x^2+8x^2-2x+4x+4+4

(3x^3+14x^2+2x+8)

3x^3+8x^2-2x+4)
6x^2+4x+4

3x^3+14x^2+2x+8

bobbym · 2011-08-18 07:25:33

1) Correct!

2) Correct!

3) Correct!

4) Correct!

5) Correct!

zee-f · 2011-08-19 00:24:50

thaaaaank you ) ill post the rest later )))

bobbym · 2011-08-19 00:31:56

Yikes! You mean there is more! I thought we ran out!

zee-f · 2011-08-19 00:49:45

yup theres more u give up ??

bobbym · 2011-08-19 00:56:54

Hah! Of course not! I never surrender!

reconsideryouranswer · 2011-08-19 16:47:56

zee-f wrote:

2. Is sqrt(x) 7 a polynomial? Explain why or why not.

no sqrt(x) 7 is not a polynomial because
it has the variable inside a radical.

zee-f · 2011-08-20 00:16:49

hi reconsideryouranswer i got my answer from the online lesson that i take this is what it says in the

lesson :6x^ 2 NOT a polynomial term This has a negative exponent.

1/x^2 NOT a polynomial term This has the variable in the denominator.

sqrt(x) NOT a polynomial term This has the variable inside a radical.

4x2 a polynomial term

bobbym · 2011-08-20 00:27:05

Hi zee-f;

Generally he is correct, if you were to phrase it that way for any expression you would run into the examples he gives. But for your specific case it is okay to phrase it that way because further simplification is impossible.

zee-f · 2011-08-20 00:39:57

hi bobbym
yes he is generally right but for my teacher am ganna post that answer

these are the rest of the question i need help seeing if there correct

6. Simplify (5x^4 3x^2 + 7x 10) (2x^4 3x^3 + 6x 17)
6- 5x^4 3x^2+7x-10
2x^4-3x^3+6x-17
(3x^4-3x^2+3x^2+x+7)

7. Multiply 9x^3(4x + 7)
7-
9x^3*4x+9x^3*7
36x^3+63x^3= (99x^6)

8. Multiply (3x 1)(5x 9)
8- (3x*5x)-(3x*-9)-(-1*5)-(-1*-9)

(15x^2-27x-5x+9)

(15x^2-32x+9)

bobbym · 2011-08-20 00:52:01

Hi;

6) Has a typo, do you see it?

zee-f · 2011-08-20 01:12:29

nope

6-
5x^4 3x^2+7x-10

2x^4-3x^3+6x-17

(3x^4-3x^2+3x^2+x+7)

bobbym · 2011-08-20 01:15:01

You do not see it? You have two 3x^2

zee-f · 2011-08-20 01:25:47

yup i see it and i cant combine 3x^3+3x^2 (3x^4-3x^3+3x^2+x+7)

zee-f · 2011-08-20 01:27:06

3x^3+3x^2 (3x^4-3x^3+3x^2+x+7)

but cant i add the 3x^2 + x to get 3x^3

bobbym · 2011-08-20 01:28:56

Hi;

(3x^4-3x^3+3x^2+x+7)

This is incorrect. Please do it again and be careful with your signs!

zee-f · 2011-08-20 01:33:07

can i add the 3x^2 + x to get 3x^3

bobbym · 2011-08-20 01:37:21

Of course not. Only expressions that are the same can be added.

zee-f · 2011-08-20 01:43:57

[(5x^4 3x^2 + 7x 10)] [(2x^4 3x^3 + 6x 17)]
( 5x^4 3x^2+7x-10)
(2x^4-3x^3+6x-17)

(3x^4-3x^2+1x+7-3x^3)

bobbym · 2011-08-20 01:48:13

Still incorrect. Please do them one at a time and post them. First one:

zee-f · 2011-08-20 01:56:07

ok and i cant subtract the 3x^2 from 3x^3 so i put

3x^4-3x^2--3x^3

bobbym · 2011-08-20 01:57:19

Please look at what I did in post #20 and you will see your error.

zee-f · 2011-08-20 02:05:10

how did u get the zero ???

bobbym · 2011-08-20 02:08:10

Hi;

Remember subtraction with numbers. Things were in columns, same thing here.

(5x^4 3x^2 + 7x 10)
-(2x^4 3x^3 + 6x 17)
-------------------------------------------

zee-f · 2011-08-20 02:11:58

yeah thats how i solved mine when i wrote it on paper but the 3x^3 and 3x^2 dont have the same exponents so there not like terms so dont i just drag them down ?

Math Is Fun Forum

#1 2011-08-18 07:18:23

review

#2 2011-08-18 07:25:33

Re: review

#3 2011-08-19 00:24:50

Re: review

#4 2011-08-19 00:31:56

Re: review

#5 2011-08-19 00:49:45

Re: review

#6 2011-08-19 00:56:54

Re: review

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Re: review

#8 2011-08-20 00:16:49

Re: review

#9 2011-08-20 00:27:05

Re: review

#10 2011-08-20 00:39:57

Re: review

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Re: review

#12 2011-08-20 01:12:29

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Re: review

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#16 2011-08-20 01:28:56

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#17 2011-08-20 01:33:07

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#18 2011-08-20 01:37:21

Re: review

#19 2011-08-20 01:43:57

Re: review

#20 2011-08-20 01:48:13

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#25 2011-08-20 02:11:58

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