Math Is Fun Forum

planetdomi

Member

Registered: 2011-09-17

Posts: 16

more rearranging

Hi,

I was hoping someone could explain why

3/√x + √x = 3/√x + √x.√x/√X

when then simplifies further to

3+x/√x

many thanks

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: more rearranging

Hi planetdomi;

I have latexed your problem out. Check to see if it is correct.

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

planetdomi

Member

Registered: 2011-09-17

Posts: 16

Re: more rearranging

Sorry
I realise Im being dumb but I dont understand your answer.
I have clicked on the equation but it doesnt take me to an answer

thanks

Bob

Administrator

Registered: 2010-06-20

Posts: 10,583

Re: more rearranging

hi planetdomi

We try to use the code language Latex for maths expressions and all bobbym was trying to check was that he had got the question right.

I'll assume he has and carry on from there.

As one term is a fraction and the other isn't (yet) one way to simplify is to put both terms over the same demoninator:

Bob

Last edited by Bob (2011-09-22 23:58:05)

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reconsideryouranswer

Member

Registered: 2011-05-11

Posts: 171

Re: more rearranging

Hi,

I was hoping someone could explain why

3/√x + √x = 3/√x + √x.√x/√X

when then simplifies further to

3+x/√x

many thanks

planetdomi,

you need grouping symbols.  For example,
you must enclose the numerator for your final expression.
The product of that fraction in your first line worked out
because of a fluke.  Also, use the same lower case letter
throughout the exercise for the same variable. 

Look at this:

3/√x + √x =

3√x  + (√x/1)(√x/√x) =

3/√x + x/√x =

(3 + x)/√x

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