Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,560

With some help I have now expanded our Sam Loyd Puzzles to more than 30.

Most of them with beautiful old illustrations.

See if you can solve them all!

Give me feedback here, too.

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

Offline

**WildJazie****Member**- Registered: 2007-07-25
- Posts: 1

Awesome collection, I hope you keep adding to it. They are fun to play with.

Offline

**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,560

Thanks WildJazie!

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

Offline

**John E. Franklin****Member**- Registered: 2005-08-29
- Posts: 3,588

On the "Question Of Time" problem, there are also other answers close to the following times:

**igloo** **myrtilles** **fourmis**

Offline

**logical1****Member**- Registered: 2012-11-02
- Posts: 3

Love the Sam Loyd Puzzles, but have a discrepancy on the keys puzzle.

The key sentence for me was "since 6910 multiplied by 7 does not equal 83452". This implies that if it did equal 83452, that the arrangement of keys would be correct. Solving it along this line, I took the factors of 83452, and found that 20863 multiplied by 4 does equal 83452, so that is my answer. Did I miss something???

Offline

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,916

hi logical1

20863 multiplied by 4 does equal 83452

It does, but I think you are mis-interpreting what the puzzle is asking.

The picture shows ten keys with the digits 0 1 2 3 4 5 6 7 8 and 9 on them.

So you need to find an answer of the form <number A> times <number B> = <number C> where exactly the ten digits are used.

And the circular order of the digits must be maintained. So you could have eg. <5269107834> as the ring is endless.

The solution given does that. Yours has repeated digits and no 1, 7, or 9.

What I'm wondering is "Is this answer the only possibility?"

Over to you. (You did say you love puzzles)

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**logical1****Member**- Registered: 2012-11-02
- Posts: 3

Thanks for the input, Bob! I didn't even notice that fact! I am going back to the puzzle to see what that looked like, re-reading the puzzle, and then considering your question. Thanks for the challenge Bob, I'll get back to you on that!

Di aka logical1

Offline

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,916

Excellent!

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

Pages: **1**