You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 93,746

Hi;

This problem was posted by our own Agnishom in another thread.

Agnishom wrote:

A triangle has sides of length at most 2, 3 & 4. What is the maximum area the triangle can have?

Let's see if geogebra 4.27 can lend some insight into the problem.

1) Hide the xy axes.

2) Place point A anywhere on the screen.

3) Use the circle with center and radius tool and click on point A and enter a radius of 2.

4) Use the point on object tool to create a point B on the circle's circumference. See the first drawing.

5) Use the circle with center and radius tool and click on point B and enter a radius of 3. A second circle will be created.

6) Use the point on object tool to create a point C on the larger circle's circumference. See the second drawing.

7) Use the polygon tool and click A, B, C, and back to A. A triangle will be created with sides AB = 2 and BC = 3. Move the three vertices around to see that those sides are constant. See fig 3.

You can see on the left the brown algebra pane which gived the sides and the areas of that triangle.

8) Set rounding to 15 decimal places in options. Play with points B and C carefully with your mouse or shift right, left arrows and try get the largest area for poly1 while keeping b < = 4.

It is not too difficult to reach poly1 = 2.999992275497143. if you are lucky you will even get poly1 = 3. No matter how hard you try you will not get an area bigger than 3. Once you are satisfied with your value use the angle tool to measure angle ABC. I got α = 89.86997934032091°. Hence the assumption of 90°, which yields sides of 2,3, √(13), with a maximum area of 3.

What has been accomplished here? For one thing we have a conjecture for the 3rd side and the conjecture that this has to be a right triangle. This helps in looking in the literature for a possible answer based on that. Or might guide us in looking for an answer.

If we are are unable to find the maximum we at least have a good estimate.

**In mathematics, you don't understand things. You just get used to them.**

**I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.**

Offline

**scientia****Member**- Registered: 2009-11-13
- Posts: 222

http://www.bmoc.maths.org/solutions/bmo1-2013/

Problem no. 5 there.

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 93,746

Hi scientia;

Thanks for that, the purpose of this was to demonstrate how a conjecture could be formed or gain some insight into how this might be solved. It is often easier to back engineer from some answer to the question.

I will now watch it and see if I came close as I thought. And thanks again for finding the video!

**In mathematics, you don't understand things. You just get used to them.**

**I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.**

Offline

Sorry, I forgot to visit this

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

'You have made another human being happy. There is no greater accomplishment.' -bobbym

Offline

Pages: **1**