Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#51 2012-12-27 07:08:34

bobbym

Offline

Re: A nice diophantine equation.

Check the post above you.

But now I am getting

That one works!!!!! Shortest one yet!

But if you use knowledge of landau notation you can see how we could derived it from my answer!

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#52 2012-12-27 07:20:06

anonimnystefy
Real Member

Offline

Re: A nice diophantine equation.

Ah, I know what my mistake was! I calculated Gamma(3) to be 6!!!

Yes, it looks like it should be n^2/60.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#53 2012-12-27 07:21:09

bobbym

Offline

Re: A nice diophantine equation.

Do you see how we could have gotten it from mine? The n^2/60 term is dominant for large n.

A really cool answer don't you think!

I will see you later, chores to do and thanks for working on the problem. You did great work with the formula.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

anonimnystefy
Real Member

Offline